What is the domain of h(x)=sqrt(x+16) ?

The domain of h(x)=sqrt(x+16) is x>=-16

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domain of h(x)=sqrt(x+16)

domain

h (x) = x + 16

x \geq - 16

Interval Notation

[- 16, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 16

The function domain

x \geq - 16

ln (x - 7)

ln (x - 9)

f (x) = - 0. 2^{2 - x} - 2

f (x) = \frac{x}{2 x - 3}

f (x) = (x + 5)^{2} - 3