What is the domain of f(x)=sqrt(2x^2-7x-15) ?

The domain of f(x)=sqrt(2x^2-7x-15) is x = 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(2x^2-7x-15)

domain

f (x) = 2 x^{2} - 7 x - 15

x \leq - \frac{3}{2} or x \geq 5

Interval Notation

(- \infty, - \frac{3}{2}] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{3}{2} or x \geq 5

The function domain

x \leq - \frac{3}{2} or x \geq 5

arcsin (x^{2})

f (x) = e^{x} - 5

y = \frac{1}{2} x + 5

2 + 5 + 6 x

f (x) = x^{2} e - x

What is the domain of f(x)=sqrt(2x^2-7x-15) ?
The domain of f(x)=sqrt(2x^2-7x-15) is x<=-3/2 \lor x>= 5