What is the domain of f(x)=2arctan(sqrt(x)+9)+5 ?

The domain of f(x)=2arctan(sqrt(x)+9)+5 is x>= 0

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domain of f(x)=2arctan(sqrt(x)+9)+5

domain

f (x) = 2 arctan (x + 9) + 5

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

f (x) = sin (- 1 (x))

ln (x) - 1

f (x) = \frac{1}{cos ( x )}

\frac{5 x ^{3} - 15 x ^{2} + 9 x - 27}{x ^{2} + 9}

f (x) = 2 - x^{2} - 3 x + 2 5 - x + x - 5

What is the domain of f(x)=2arctan(sqrt(x)+9)+5 ?
The domain of f(x)=2arctan(sqrt(x)+9)+5 is x>= 0