What is the domain of f(x)=sqrt(3+ln(x)) ?

The domain of f(x)=sqrt(3+ln(x)) is x>= 1/(e^3)

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domain of f(x)=sqrt(3+ln(x))

domain

f (x) = 3 + ln (x)

x \geq \frac{1}{e ^{3}}

Interval Notation

[\frac{1}{e ^{3}}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{e ^{3}}

The function domain

x \geq \frac{1}{e ^{3}}

\frac{x - 6}{2 x + 3}

f (x) = \frac{1 + x - 3 x ^{2}}{x x ^{2} - 4}

(x - 3)^{2} + 4

f (x) = x e^{2 x}

f (x) = (x^{2} + 2) (x - 2)

What is the domain of f(x)=sqrt(3+ln(x)) ?
The domain of f(x)=sqrt(3+ln(x)) is x>= 1/(e^3)