What is the domain of f(x)=\sqrt[3]{(3x)/(x^2-3)} ?

The domain of f(x)=\sqrt[3]{(3x)/(x^2-3)} is x sqrt(3)

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domain of f(x)=\sqrt[3]{(3x)/(x^2-3)}

domain

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

x^{5} - 1

g (x) = \frac{4}{2 x + 8} + 1

\frac{x - 4}{x ^{2} + 8 x + 16}

f (x) = \frac{1}{2} x + 2

What is the domain of f(x)=\sqrt[3]{(3x)/(x^2-3)} ?
The domain of f(x)=\sqrt[3]{(3x)/(x^2-3)} is x<-sqrt(3)\lor-sqrt(3)<x<sqrt(3)\lor x>sqrt(3)