What is the domain of g(x)= 1/(sqrt(x)) ?

The domain of g(x)= 1/(sqrt(x)) is x>0

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domain of g(x)= 1/(sqrt(x))

domain

g (x) = \frac{1}{x}

x > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

f (x) = 2 x - 4 + \frac{1}{x - 2}

\frac{x + 6}{x ^{2} + x - 6}

f (x) = \frac{8}{x - 5}

f (x) = 3 cos (x) - 1

f (x) = \frac{x - 3}{x ^{2} + 4 x - 21}

What is the domain of g(x)= 1/(sqrt(x)) ?
The domain of g(x)= 1/(sqrt(x)) is x>0