What is the domain of f(x)=(sqrt(x))^2 ?

The domain of f(x)=(sqrt(x))^2 is x>= 0

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domain of f(x)=(sqrt(x))^2

domain

f (x) = (x)^{2}

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

f (x) = \frac{- x ( 1 - x )}{3 x ^{2} + 5 x - 2}

f (x) = \frac{x + 2}{3 x ^{2} + 7 x + 4}

f (x) = 2^{x + 1} - 2

\frac{x + 4}{5}

What is the domain of f(x)=(sqrt(x))^2 ?
The domain of f(x)=(sqrt(x))^2 is x>= 0