What is the domain of f(x)=sqrt((\sqrt{x-1))+1} ?

The domain of f(x)=sqrt((\sqrt{x-1))+1} is x>= 1

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domain of f(x)=sqrt((\sqrt{x-1))+1}

domain

f (x) = (x - 1) + 1

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

f (x) = \frac{3 ^{2 x + 1}}{4}

f (x) = \frac{5 x ^{2} + 7 x - 13}{3 x ^{2} + 5 x - 2}

f (x) = \frac{x ^{2} - 9}{x + 1}

x^{2} + 6 x - 5

g (x) = \frac{x}{x ^{2} - 4}

What is the domain of f(x)=sqrt((\sqrt{x-1))+1} ?
The domain of f(x)=sqrt((\sqrt{x-1))+1} is x>= 1