What is the domain of f(x)=(x^3+x+8)/(x^4-1) ?

The domain of f(x)=(x^3+x+8)/(x^4-1) is x 1

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domain of f(x)=(x^3+x+8)/(x^4-1)

domain

f (x) = \frac{x ^{3} + x + 8}{x ^{4} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = x + 5 = 0

\frac{x ^{2} - 3}{x ^{3} - 27}

f (x) = 0.5 cos (x) - 0.75

3 - \frac{1}{x - 1}

arccsc (x)

What is the domain of f(x)=(x^3+x+8)/(x^4-1) ?
The domain of f(x)=(x^3+x+8)/(x^4-1) is x<-1\lor-1<x<1\lor x>1