What is the domain of f(x)=(sqrt(x-2))/(x^2-36) ?

The domain of f(x)=(sqrt(x-2))/(x^2-36) is 2 6

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domain of f(x)=(sqrt(x-2))/(x^2-36)

domain

f (x) = \frac{x - 2}{x ^{2} - 36}

2 \leq x < 6 or x > 6

Interval Notation

[2, 6) \cup (6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 6, x = - 6

Combine real regions and undefined points for final function domain

2 \leq x < 6 or x > 6

- 2 ln (x + 1)

f (x) = 5^{x + 2}

f (x) = \frac{x - 2}{5 x + \frac{1}{2}}

x^{2} - x - 2

x^{2} - x - 1

What is the domain of f(x)=(sqrt(x-2))/(x^2-36) ?
The domain of f(x)=(sqrt(x-2))/(x^2-36) is 2<= x<6\lor x>6