What is the domain of arccos(1/x) ?

The domain of arccos(1/x) is x = 1

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domain of arccos(1/x)

domain

arccos (\frac{1}{x})

x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 1] \cup [1, \infty)

Solution steps

Find known functions domain restrictions:

x \leq - 1 or x \geq 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x \leq - 1 or x \geq 1

f (x) = \frac{1}{x ^{2}} - 2

\frac{5}{9 + x}

f (x) = \frac{x - 3}{x ^{2} - 2}

f (x) = \frac{x ^{3} + 3 x ^{2} + 2 x}{x ^{2} + 3 x + 2}

\frac{x}{- 8 x + 81}

What is the domain of arccos(1/x) ?
The domain of arccos(1/x) is x<=-1\lor x>= 1