What is the domain of f(x)=(x-2)/(2x^2+x-10) ?

The domain of f(x)=(x-2)/(2x^2+x-10) is x 2

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domain of f(x)=(x-2)/(2x^2+x-10)

domain

f (x) = \frac{x - 2}{2 x ^{2} + x - 10}

x < - \frac{5}{2} or - \frac{5}{2} < x < 2 or x > 2

Interval Notation

(- \infty, - \frac{5}{2}) \cup (- \frac{5}{2}, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - \frac{5}{2}

The function domain

x < - \frac{5}{2} or - \frac{5}{2} < x < 2 or x > 2

f (x) = \frac{x - 4}{2 x + 2}

\frac{2}{x ^{2} - 2 x - 35}

f (x) = ln (x + 5 - 1)

f (x) = x^{3} - 4 x^{2}

What is the domain of f(x)=(x-2)/(2x^2+x-10) ?
The domain of f(x)=(x-2)/(2x^2+x-10) is x<-5/2 \lor-5/2 <x<2\lor x>2