What is the domain of f(x)=(x^2+3x-1)/(4x^2-3x-1) ?

The domain of f(x)=(x^2+3x-1)/(4x^2-3x-1) is x 1

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domain of f(x)=(x^2+3x-1)/(4x^2-3x-1)

domain

f (x) = \frac{x ^{2} + 3 x - 1}{4 x ^{2} - 3 x - 1}

x < - \frac{1}{4} or - \frac{1}{4} < x < 1 or x > 1

Interval Notation

(- \infty, - \frac{1}{4}) \cup (- \frac{1}{4}, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - \frac{1}{4}

The function domain

x < - \frac{1}{4} or - \frac{1}{4} < x < 1 or x > 1

arccos (e^{x - 1}) + π

arctan^{x} (x)

f (x) = ∣ x ∣ + 12

f (x) = \frac{2}{5 x + 8}

f (x) = \frac{2 x - 1}{1 - x}

What is the domain of f(x)=(x^2+3x-1)/(4x^2-3x-1) ?
The domain of f(x)=(x^2+3x-1)/(4x^2-3x-1) is x<-1/4 \lor-1/4 <x<1\lor x>1