What is the domain of f(x)=\sqrt[4]{x^2+6x} ?

The domain of f(x)=\sqrt[4]{x^2+6x} is x = 0

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domain of f(x)=\sqrt[4]{x^2+6x}

domain

x \leq - 6 or x \geq 0

Interval Notation

(- \infty, - 6] \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 6 or x \geq 0

The function domain

x \leq - 6 or x \geq 0

f (x) = \frac{3 x + 4}{2 x - 1}

f (x) = \frac{x - 1}{x ^{2} - 2 x + 1}

\frac{8 - x}{7 x + 21}

f (x) = \frac{x ^{2}}{5}

f (x) = 13 x

What is the domain of f(x)=\sqrt[4]{x^2+6x} ?
The domain of f(x)=\sqrt[4]{x^2+6x} is x<=-6\lor x>= 0