What is the domain of f(x)=(sqrt(x+2))/(x^2-9) ?

The domain of f(x)=(sqrt(x+2))/(x^2-9) is -2 3

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domain of f(x)=(sqrt(x+2))/(x^2-9)

domain

f (x) = \frac{x + 2}{x ^{2} - 9}

- 2 \leq x < 3 or x > 3

Interval Notation

[- 2, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

- 2 \leq x < 3 or x > 3

f (x) = ln (x - 3) + 4

lo g_{10} (1 - x^{2})

f (x) = - x^{2} + 6 x - 8

f (x) = x - x

g (x) = 2 (x - 1) 2 - 3

What is the domain of f(x)=(sqrt(x+2))/(x^2-9) ?
The domain of f(x)=(sqrt(x+2))/(x^2-9) is -2<= x<3\lor x>3