What is the domain of f(x)= 1/(log_{x+1)(2)} ?

The domain of f(x)= 1/(log_{x+1)(2)} is -1 0

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domain of f(x)= 1/(log_{x+1)(2)}

domain

f (x) = \frac{1}{lo g _{x + 1} ( 2 )}

- 1 < x < 0 or x > 0

Interval Notation

(- 1, 0) \cup (0, \infty)

Solution steps

Check value of logs base:

- 1 < x < 0 or x > 0

The function domain

- 1 < x < 0 or x > 0

\frac{x + 7}{2 x - 2}

f (x) = \frac{3 x + 8}{- x ^{2} - 6 x + 16}

f (x) = \frac{x - 1}{x + 1}

f (x) = \frac{13}{3 x + 13}

f (x) = x^{2} + 8 x - 20

What is the domain of f(x)= 1/(log_{x+1)(2)} ?
The domain of f(x)= 1/(log_{x+1)(2)} is -1<x<0\lor x>0