What is the domain of f(x)=sqrt(x^2-16)*(x^2+x-2) ?

The domain of f(x)=sqrt(x^2-16)*(x^2+x-2) is x = 4

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domain of f(x)=sqrt(x^2-16)*(x^2+x-2)

domain

f (x) = x^{2} - 16 \cdot (x^{2} + x - 2)

x \leq - 4 or x \geq 4

Interval Notation

(- \infty, - 4] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 4

The function domain

x \leq - 4 or x \geq 4

\frac{x ^{3} - 27}{x}

x^{2} + 5 x - 6

- \frac{5 x}{x - 6}

y = \frac{3 x + 5}{x - 1}

f (x) = x - 3 x^{\frac{2}{3}}

What is the domain of f(x)=sqrt(x^2-16)*(x^2+x-2) ?
The domain of f(x)=sqrt(x^2-16)*(x^2+x-2) is x<=-4\lor x>= 4