What is the domain of y=(2x^2-6+4)/(-3x-5) ?

The domain of y=(2x^2-6+4)/(-3x-5) is x -5/3

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domain of y=(2x^2-6+4)/(-3x-5)

domain

y = \frac{2 x ^{2} - 6 + 4}{- 3 x - 5}

x < - \frac{5}{3} or x > - \frac{5}{3}

Interval Notation

(- \infty, - \frac{5}{3}) \cup (- \frac{5}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{5}{3}

The function domain

x < - \frac{5}{3} or x > - \frac{5}{3}

∣ x + 3 ∣

2^{x - 1} - 2

f (x) = 7 - 9 - 3 x

2 - 3 x

f (x) = \frac{3 - x ^{2} - 7}{x - 4}

What is the domain of y=(2x^2-6+4)/(-3x-5) ?
The domain of y=(2x^2-6+4)/(-3x-5) is x<-5/3 \lor x>-5/3