What is the domain of f(x)=(x-9)/(x^2-64) ?

The domain of f(x)=(x-9)/(x^2-64) is x 8

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domain of f(x)=(x-9)/(x^2-64)

domain

f (x) = \frac{x - 9}{x ^{2} - 64}

x < - 8 or - 8 < x < 8 or x > 8

Interval Notation

(- \infty, - 8) \cup (- 8, 8) \cup (8, \infty)

Solution steps

Find undefined (singularity) points:

x = 8, x = - 8

The function domain

x < - 8 or - 8 < x < 8 or x > 8

f (x) = \frac{5 x - 1}{- x + 2}

\frac{x - 2}{x - 9}

f (x) = \frac{x ^{3} - 12}{x ^{2} + 16}

\frac{x - 6}{x - 4}

f (x) = \frac{1 - e ^{2 x}}{2 + e ^{2 x}}

What is the domain of f(x)=(x-9)/(x^2-64) ?
The domain of f(x)=(x-9)/(x^2-64) is x<-8\lor-8<x<8\lor x>8