What is the domain of y=ln(x^2-1)+arcsin(1/(x+1)) ?

The domain of y=ln(x^2-1)+arcsin(1/(x+1)) is x 1

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domain of y=ln(x^2-1)+arcsin(1/(x+1))

domain

y = ln (x^{2} - 1) + arcsin (\frac{1}{x + 1})

x \leq - 2 or x > 1

Interval Notation

(- \infty, - 2] \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > 1

Find known functions domain restrictions:

x \leq - 2 or x \geq 0

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x \leq - 2 or x > 1

f (x) = \frac{3}{cos ( x )}

lo g_{10} (2 x - x^{2})

\frac{5}{5 n - 25}

f (x) = (- \frac{4 e ^{x}}{3} - 3)

cos (2 t)

What is the domain of y=ln(x^2-1)+arcsin(1/(x+1)) ?
The domain of y=ln(x^2-1)+arcsin(1/(x+1)) is x<=-2\lor x>1