What is the domain of f(x)=e^z+4x^2+9y^2=1 ?

The domain of f(x)=e^z+4x^2+9y^2=1 is -infinity <x<infinity

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domain of f(x)=e^z+4x^2+9y^2=1

domain

f (x) = e^{z} + 4 x^{2} + 9 y^{2} = 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{3 x ^{2} - 2 x - 8}{x ^{2} + 3 x - 10}

y = 8 x - 2

2 cos (3 x + π)

lo g_{10} (2) (x + 2) + 5

2 sin (\frac{1}{4}) (y + \frac{π}{4}) - 1

What is the domain of f(x)=e^z+4x^2+9y^2=1 ?
The domain of f(x)=e^z+4x^2+9y^2=1 is -infinity <x<infinity