What is the domain of f(x)=(6x-25)/(-5x+41) ?

The domain of f(x)=(6x-25)/(-5x+41) is x 41/5

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domain of f(x)=(6x-25)/(-5x+41)

domain

f (x) = \frac{6 x - 25}{- 5 x + 41}

x < \frac{41}{5} or x > \frac{41}{5}

Interval Notation

(- \infty, \frac{41}{5}) \cup (\frac{41}{5}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{41}{5}

The function domain

x < \frac{41}{5} or x > \frac{41}{5}

f (x) = \frac{x + 4}{x - 6}

e^{- 2 x}

f (x) = \frac{x + 4}{x - 1}

lo g_{2} (x^{2} - x - 90)

9 x + 5

What is the domain of f(x)=(6x-25)/(-5x+41) ?
The domain of f(x)=(6x-25)/(-5x+41) is x< 41/5 \lor x> 41/5