What is the domain of f(x)=(sqrt(x+1))/(x-5) ?

The domain of f(x)=(sqrt(x+1))/(x-5) is -1 5

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domain of f(x)=(sqrt(x+1))/(x-5)

domain

f (x) = \frac{x + 1}{x - 5}

- 1 \leq x < 5 or x > 5

Interval Notation

[- 1, 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

- 1 \leq x < 5 or x > 5

sin (\frac{1}{x})

f (x) = - (x + 1)^{2}

y = - 3 - 2 x + 8 + 5

f (x) = arccos (\frac{x}{2} + 1)

f (x) = \frac{2 x - 8}{9 x + 54}

What is the domain of f(x)=(sqrt(x+1))/(x-5) ?
The domain of f(x)=(sqrt(x+1))/(x-5) is -1<= x<5\lor x>5