What is the domain of f(x)=xsqrt(x+1) ?

The domain of f(x)=xsqrt(x+1) is x>=-1

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domain of f(x)=xsqrt(x+1)

domain

f (x) = x x + 1

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

y = 5 x - 10

f (x) = - x^{2} + 9

f (x) = \frac{x}{x ^{2} - 4}

f (x) = x^{2} + 4 x + 1

\frac{7 x + 2}{x - 2}