What is the domain of f(x)=sqrt(6x-2) ?

The domain of f(x)=sqrt(6x-2) is x>= 1/3

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domain of f(x)=sqrt(6x-2)

domain

f (x) = 6 x - 2

x \geq \frac{1}{3}

Interval Notation

[\frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{3}

The function domain

x \geq \frac{1}{3}

\frac{x ^{2} - 49}{x - 3}

f (x) = ln (- x^{2} + 4 x)

\frac{x + 2}{2}

y = 2 + x^{2}

h (x) = x + 7

What is the domain of f(x)=sqrt(6x-2) ?
The domain of f(x)=sqrt(6x-2) is x>= 1/3