What is the domain of f(x)=(6/x)/(1/(x^2-1)) ?

The domain of f(x)=(6/x)/(1/(x^2-1)) is x 1

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domain of f(x)=(6/x)/(1/(x^2-1))

domain

f (x) = \frac{\frac{6}{x}}{\frac{1}{x ^{2} - 1}}

x < - 1 or - 1 < x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 0 or 0 < x < 1 or x > 1

3 t

f (x) = \frac{x - 1}{x - 4}

2 (x - 1)^{2} - 3

lo g_{9} (x)

f (x) = \frac{3 x ^{2} + 6}{x ^{2} - 2 x - 3}

What is the domain of f(x)=(6/x)/(1/(x^2-1)) ?
The domain of f(x)=(6/x)/(1/(x^2-1)) is x<-1\lor-1<x<0\lor 0<x<1\lor x>1