What is the domain of sqrt(49-s^2) ?

The domain of sqrt(49-s^2) is -7<= s<= 7

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domain of sqrt(49-s^2)

domain

49 - s^{2}

- 7 \leq s \leq 7

Interval Notation

[- 7, 7]

Solution steps

Find non-negative values for radicals:

- 7 \leq s \leq 7

The function domain

- 7 \leq s \leq 7

f (x) = 2 (x + 3)^{2} - 5

- \frac{b - 2 y}{y}

f (x) = - 4 - 2 x - 3

y = x^{3} + 2 x^{2}

f (x) = \frac{x ^{3} + 1}{x ^{2} - 1}