What is the domain of (1+sqrt(1-4x^2))/(2x) ?

The domain of (1+sqrt(1-4x^2))/(2x) is -1/2 <= x<0\lor 0<x<= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (1+sqrt(1-4x^2))/(2x)

domain

\frac{1 + 1 - 4 x ^{2}}{2 x}

- \frac{1}{2} \leq x < 0 or 0 < x \leq \frac{1}{2}

Interval Notation

[- \frac{1}{2}, 0) \cup (0, \frac{1}{2}]

Solution steps

Find non-negative values for radicals:

- \frac{1}{2} \leq x \leq \frac{1}{2}

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- \frac{1}{2} \leq x < 0 or 0 < x \leq \frac{1}{2}

f (x) = 2^{x - 2}

f (x) = e^{x}

\frac{( 5 x + 4 ) ( x + 1 )}{( 2 x + 1 ) ( 3 x + 5 )}

f (x) = lo g_{3} ((1 + y)^{2}) = 2

f (x) = 2 tan (3 t - π)

What is the domain of (1+sqrt(1-4x^2))/(2x) ?
The domain of (1+sqrt(1-4x^2))/(2x) is -1/2 <= x<0\lor 0<x<= 1/2