What is the domain of f(x)=sqrt(((x+1)(x+2))/(x-3)) ?

The domain of f(x)=sqrt(((x+1)(x+2))/(x-3)) is -2 3

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domain of f(x)=sqrt(((x+1)(x+2))/(x-3))

domain

f (x) = \frac{( x + 1 ) ( x + 2 )}{x - 3}

- 2 \leq x \leq - 1 or x > 3

Interval Notation

[- 2, - 1] \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq - 1 or x > 3

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

- 2 \leq x \leq - 1 or x > 3

f (x) = 4 sin (x) cos (x)

10 - x^{2}

\frac{7 x}{6 x - 5}

(- \frac{1}{x}) \cdot \frac{1 - x}{1 + x} \cdot \frac{x}{x ^{2} - 1}

f (x) = 2 ln (x^{2} + 2) - 1

What is the domain of f(x)=sqrt(((x+1)(x+2))/(x-3)) ?
The domain of f(x)=sqrt(((x+1)(x+2))/(x-3)) is -2<= x<=-1\lor x>3