What is the domain of f(x)=sqrt((x^2-9)+5) ?

The domain of f(x)=sqrt((x^2-9)+5) is x = 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt((x^2-9)+5)

domain

f (x) = (x^{2} - 9) + 5

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

ln (5 x - 2)

f (x) = \frac{x}{10 x + 81}

3 x^{2} - 2 x + 1

f (x) = \frac{- 2 x}{( x + 7 ) ( 6 - x )}

f (x) = x + (\frac{1}{x})

What is the domain of f(x)=sqrt((x^2-9)+5) ?
The domain of f(x)=sqrt((x^2-9)+5) is x<=-2\lor x>= 2