What is the inverse of f(x)=sqrt(-x^2+20x-25)+10 ?

The inverse of f(x)=sqrt(-x^2+20x-25)+10 is 10-sqrt(-x^2+20x-25),sqrt(-x^2+20x-25)+10

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inverse of f(x)=sqrt(-x^2+20x-25)+10

inverse

f (x) = - x^{2} + 20 x - 25 + 10

10 - - x^{2} + 20 x - 25, - x^{2} + 20 x - 25 + 10

Solution steps

y = - x^{2} + 20 x - 25 + 10

Replace

x

with

y

x = - y^{2} + 20 y - 25 + 10

Solve for

y, x = - y^{2} + 20 y - 25 + 10

10 - - x^{2} + 20 x - 25, - x^{2} + 20 x - 25 + 10

g (t) = \frac{7}{t}

(- 4, - 8), (8, 10)

f (x) = 16 x - 8 x^{2}

2 ∣ x ∣

x + y = 5

What is the inverse of f(x)=sqrt(-x^2+20x-25)+10 ?
The inverse of f(x)=sqrt(-x^2+20x-25)+10 is 10-sqrt(-x^2+20x-25),sqrt(-x^2+20x-25)+10