What is the domain of f(x)= 2/(1-cos(x)) ?

The domain of f(x)= 2/(1-cos(x)) is 2pin<x<2pi+2pin

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domain of f(x)= 2/(1-cos(x))

domain

f (x) = \frac{2}{1 - cos ( x )}

2 πn < x < 2 π + 2 πn

Interval Notation

(2 πn, 2 π + 2 πn)

Solution steps

Take the denominator(s) of

\frac{2}{1 - cos ( x )}

and compare to zero:

x = 2 πn

Periodicity of

\frac{2}{1 - cos ( x )} : 2 π

Combine period:

2 πn \leq x < 2 π + 2 πn

and undefined points.

The domain is

2 πn < x < 2 π + 2 πn

f (x) = \frac{( 5 ln ( x ) )}{x ^{3}}

\frac{x ^{2} - 2}{x ^{2} - 4}

ln (e^{x} - 8) + 5

f (x) = \frac{5 t + 1}{t ^{3} - t ^{2} - 8 t}

f (x) = \frac{x + 2}{x - 6}

What is the domain of f(x)= 2/(1-cos(x)) ?
The domain of f(x)= 2/(1-cos(x)) is 2pin<x<2pi+2pin