What is the domain of f(x)= 1/9 x^2 ?

The domain of f(x)= 1/9 x^2 is -infinity <x<infinity

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domain of f(x)= 1/9 x^2

domain

f (x) = \frac{1}{9} x^{2}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{2 x + 1}{3 x - 4}

y = \frac{3}{2} x^{2} - 3 x + 4

y = 2 x^{2} + 1

\frac{1}{2} x - 5

\frac{1}{2} x + 1

What is the domain of f(x)= 1/9 x^2 ?
The domain of f(x)= 1/9 x^2 is -infinity <x<infinity