What is the domain of f(x)=ln(1/(x+8)) ?

The domain of f(x)=ln(1/(x+8)) is x>-8

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domain of f(x)=ln(1/(x+8))

domain

f (x) = ln (\frac{1}{x + 8})

x > - 8

Interval Notation

(- 8, \infty)

Solution steps

Find positive values for logs:

x > - 8

Find undefined (singularity) points:

x = - 8

Combine real regions and undefined points for final function domain

x > - 8

f (x) = \frac{x ^{2} - 16}{x}

f (x) = (\frac{3}{2})^{x + 2} - 1

f (x) = \frac{4 x ^{2} + 2 x - 2}{4 x - 2}

f (x) = x - 2005

f (x) = \frac{x}{1 - x + 1}