What is the domain of (2x^2+3)/(4x-1) ?

The domain of (2x^2+3)/(4x-1) is x 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (2x^2+3)/(4x-1)

domain

\frac{2 x ^{2} + 3}{4 x - 1}

x < \frac{1}{4} or x > \frac{1}{4}

Interval Notation

(- \infty, \frac{1}{4}) \cup (\frac{1}{4}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{4}

The function domain

x < \frac{1}{4} or x > \frac{1}{4}

\frac{x}{x - 2}

(x - 1) e^{- \frac{1}{x}}

\frac{- x ^{2} + 2 x + 15}{x + 3}

ln (\frac{2 + x}{2 - x})

f (x) = \frac{2 cos ( x ) - 1}{sin ( x ) - 1}

What is the domain of (2x^2+3)/(4x-1) ?
The domain of (2x^2+3)/(4x-1) is x< 1/4 \lor x> 1/4