What is the domain of (4x^2)/(x^2-9) ?

The domain of (4x^2)/(x^2-9) is x 3

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domain of (4x^2)/(x^2-9)

domain

\frac{4 x ^{2}}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

\frac{3 x + 12}{- 12 x + 4}

f (x) = 3 - 2 e^{\frac{- 3}{x}}

f (x) = x^{2} - 8 x + 14

f (x) = x^{2} - 8 x + 15

f (x) = \frac{x + 4}{x + 3}

What is the domain of (4x^2)/(x^2-9) ?
The domain of (4x^2)/(x^2-9) is x<-3\lor-3<x<3\lor x>3