What is the domain of (2x^2-6x+4)/(3x-5) ?

The domain of (2x^2-6x+4)/(3x-5) is x 5/3

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domain of (2x^2-6x+4)/(3x-5)

domain

\frac{2 x ^{2} - 6 x + 4}{3 x - 5}

x < \frac{5}{3} or x > \frac{5}{3}

Interval Notation

(- \infty, \frac{5}{3}) \cup (\frac{5}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{5}{3}

The function domain

x < \frac{5}{3} or x > \frac{5}{3}

- lo g_{\frac{1}{5}} (x)

f (x) = \frac{1}{( x - 2 ) ^{2}}

f (x) = \frac{3 x - 1}{- x ^{2} + x + 20}

f (x) = \frac{2 x - 1}{3}

\frac{x}{10 x + 81}

What is the domain of (2x^2-6x+4)/(3x-5) ?
The domain of (2x^2-6x+4)/(3x-5) is x< 5/3 \lor x> 5/3