What is the domain of y=(x+3)/(2x^2-2) ?

The domain of y=(x+3)/(2x^2-2) is x 1

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domain of y=(x+3)/(2x^2-2)

domain

y = \frac{x + 3}{2 x ^{2} - 2}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

\frac{5 x - 1}{2 x + 3}

f (x) = \frac{x + 7}{x ^{2} + x - 6}

y = 3 sin (x)

f (x) = 3 + 4 + 9 x

\frac{1 + x}{1 - x}

What is the domain of y=(x+3)/(2x^2-2) ?
The domain of y=(x+3)/(2x^2-2) is x<-1\lor-1<x<1\lor x>1