What is the domain of y=(sqrt(x-2)+2)/(x^2-9) ?

The domain of y=(sqrt(x-2)+2)/(x^2-9) is 2 3

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domain of y=(sqrt(x-2)+2)/(x^2-9)

domain

y = \frac{x - 2 + 2}{x ^{2} - 9}

2 \leq x < 3 or x > 3

Interval Notation

[2, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

2 \leq x < 3 or x > 3

f (x) = \frac{3}{5} x^{4} + \frac{3}{5} x^{3} + x^{2}

\frac{x + 8}{x ^{2} + 10 x + 21}

f (x) = \frac{x + 7}{3}

f (x) = - lo g_{3} (x + 2)

\frac{w}{( w - 1 ) ( w - 2 ) ( w - 3 )}

What is the domain of y=(sqrt(x-2)+2)/(x^2-9) ?
The domain of y=(sqrt(x-2)+2)/(x^2-9) is 2<= x<3\lor x>3