What is the domain of f(x)=(2x)/(sqrt(36-x)) ?

The domain of f(x)=(2x)/(sqrt(36-x)) is x<36

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domain of f(x)=(2x)/(sqrt(36-x))

domain

f (x) = \frac{2 x}{36 - x}

x < 36

Interval Notation

(- \infty, 36)

Solution steps

Find non-negative values for radicals:

x \leq 36

Find undefined (singularity) points:

x = 36

Combine real regions and undefined points for final function domain

x < 36

lo g_{10} (x - 7)

(x + 5)^{2}

f (x) = - 3 x + 6 - 2

x ((16 - 2 x) (21 - 2 x))

3 y = 10 (2)^{x + 1} - 5

What is the domain of f(x)=(2x)/(sqrt(36-x)) ?
The domain of f(x)=(2x)/(sqrt(36-x)) is x<36