What is the domain of f(x)=x^2+sqrt(x-5) ?

The domain of f(x)=x^2+sqrt(x-5) is x>= 5

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domain of f(x)=x^2+sqrt(x-5)

domain

f (x) = x^{2} + x - 5

x \geq 5

Interval Notation

[5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 5

The function domain

x \geq 5

f (x) = lo g_{10} (x^{2} + 9 x + 8)

\frac{2 x}{x - 4}

\frac{x}{- x + 4}

f (x) = - 3^{2}

e^{- x} + 1

What is the domain of f(x)=x^2+sqrt(x-5) ?
The domain of f(x)=x^2+sqrt(x-5) is x>= 5