What is the extreme f(x)=9+3x^2-2x^3 ?

The extreme f(x)=9+3x^2-2x^3 is Minimum(0,9),Maximum(1,10)

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extreme f(x)=9+3x^2-2x^3

extreme points

f (x) = 9 + 3 x^{2} - 2 x^{3}

Minimum (0, 9), Maximum (1, 10)

Solution steps

f^{'} (x) = - 6 x^{2} + 6 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 0

into

9 + 3 x^{2} - 2 x^{3} : 9

Minimum (0, 9)

Plug

x = 1

into

9 + 3 x^{2} - 2 x^{3} : 10

Maximum (1, 10)

Minimum (0, 9), Maximum (1, 10)

f (x) = \frac{( 7 )}{( 2 ) sin ( θ )}

Y (x) = x^{2} - 6

f (x) = ln (5 - 4 x^{2})

- 7 x + 4 y = 19

What is the extreme f(x)=9+3x^2-2x^3 ?
The extreme f(x)=9+3x^2-2x^3 is Minimum(0,9),Maximum(1,10)