What is the domain of (x^2+6x-16)/((x+1)(x-3)(x+8)) ?

The domain of (x^2+6x-16)/((x+1)(x-3)(x+8)) is x 3

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domain of (x^2+6x-16)/((x+1)(x-3)(x+8))

domain

\frac{x ^{2} + 6 x - 16}{( x + 1 ) ( x - 3 ) ( x + 8 )}

x < - 8 or - 8 < x < - 1 or - 1 < x < 3 or x > 3

Interval Notation

(- \infty, - 8) \cup (- 8, - 1) \cup (- 1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = 3, x = - 8

The function domain

x < - 8 or - 8 < x < - 1 or - 1 < x < 3 or x > 3

x^{2} + 49

x^{3} - 2 x^{2} - 3 x

f (x) = tanh (x)

x^{2} + 8 x + 12

ln (\frac{1}{x - 8})

What is the domain of (x^2+6x-16)/((x+1)(x-3)(x+8)) ?
The domain of (x^2+6x-16)/((x+1)(x-3)(x+8)) is x<-8\lor-8<x<-1\lor-1<x<3\lor x>3