What is the domain of f(x)=(x+3)/(x^2+x-6) ?

The domain of f(x)=(x+3)/(x^2+x-6) is x 2

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domain of f(x)=(x+3)/(x^2+x-6)

domain

f (x) = \frac{x + 3}{x ^{2} + x - 6}

x < - 3 or - 3 < x < 2 or x > 2

Interval Notation

(- \infty, - 3) \cup (- 3, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 3

The function domain

x < - 3 or - 3 < x < 2 or x > 2

y = (x - 1)^{2} (4 - x)

ln (1 + 27 x^{3})

f (x) = \frac{x ^{2} - 4}{x - 2}

π sin (2 x + 1)

f (x) = \frac{x ^{2} - 1}{x}

What is the domain of f(x)=(x+3)/(x^2+x-6) ?
The domain of f(x)=(x+3)/(x^2+x-6) is x<-3\lor-3<x<2\lor x>2