What is the domain of f(x)=sqrt(x-3)+6 ?

The domain of f(x)=sqrt(x-3)+6 is x>= 3

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domain of f(x)=sqrt(x-3)+6

domain

f (x) = x - 3 + 6

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

f (x) = \frac{( x + 2 )}{( x - 1 )}

f (x) = 14 x + 12

\frac{1}{x ^{2}} - 2

4 x^{2} + 7 x - 19

f (x) = 2^{2}

What is the domain of f(x)=sqrt(x-3)+6 ?
The domain of f(x)=sqrt(x-3)+6 is x>= 3