What is the domain of f(x)=sqrt(x^2+3x) ?

The domain of f(x)=sqrt(x^2+3x) is x = 0

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domain of f(x)=sqrt(x^2+3x)

domain

f (x) = x^{2} + 3 x

x \leq - 3 or x \geq 0

Interval Notation

(- \infty, - 3] \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 0

The function domain

x \leq - 3 or x \geq 0

f (x) = \frac{( x + 1 )}{x ^{2}}

f (x) = (lo g_{2} (x) - 1)

f (x) = \frac{x - 1}{ln ( 3 - x )}

- \frac{1}{x ^{2} 1 - x ^{2}}

x + 8

What is the domain of f(x)=sqrt(x^2+3x) ?
The domain of f(x)=sqrt(x^2+3x) is x<=-3\lor x>= 0