What is the domain of f(x)=-1-sqrt(4-x^2) ?

The domain of f(x)=-1-sqrt(4-x^2) is -2<= x<= 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=-1-sqrt(4-x^2)

domain

f (x) = - 1 - 4 - x^{2}

- 2 \leq x \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

The function domain

- 2 \leq x \leq 2

f (x) = \frac{1}{2} ln (\frac{1 + x}{1 - x})

\frac{5}{x} - 2

\frac{x - 4}{x + 2}

f (x) = lo g_{10} (3) (x)

f (x) = \frac{x + 2}{x ^{2} - 16}

What is the domain of f(x)=-1-sqrt(4-x^2) ?
The domain of f(x)=-1-sqrt(4-x^2) is -2<= x<= 2