What is the domain of (x-3)/(x^2-9) ?

The domain of (x-3)/(x^2-9) is x 3

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domain of (x-3)/(x^2-9)

domain

\frac{x - 3}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

y = \frac{1}{- 4 x ^{2} - 20 x - 21}

f (x) = \frac{x + 6}{x - 8}

g (x) = 3 x^{2} - 81

f (x) = \frac{2 x - 5}{3 + x}

8 x^{2}

What is the domain of (x-3)/(x^2-9) ?
The domain of (x-3)/(x^2-9) is x<-3\lor-3<x<3\lor x>3