What is the domain of f(x)=sqrt(x^2+2x-3) ?

The domain of f(x)=sqrt(x^2+2x-3) is x = 1

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domain of f(x)=sqrt(x^2+2x-3)

domain

f (x) = x^{2} + 2 x - 3

x \leq - 3 or x \geq 1

Interval Notation

(- \infty, - 3] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 1

The function domain

x \leq - 3 or x \geq 1

f (x) = cos (x + 1)

f (x) = \frac{x}{9 x + 6}

f (x) = \frac{( x + 1 ) ^{2}}{x ^{2} + 1}

f (x) = 2 (5)^{x} + 3

f (x) = - 9 y^{2} - 121 + 5 x^{2} + 54 y - 10 x = 0

What is the domain of f(x)=sqrt(x^2+2x-3) ?
The domain of f(x)=sqrt(x^2+2x-3) is x<=-3\lor x>= 1