What is the domain of f(x)=log_{1/2}(x-3) ?

The domain of f(x)=log_{1/2}(x-3) is x>3

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domain of f(x)=log_{1/2}(x-3)

domain

f (x) = lo g_{\frac{1}{2}} (x - 3)

x > 3

Interval Notation

(3, \infty)

Solution steps

Find positive values for logs:

x > 3

The function domain

x > 3

f (x) = - 3^{- 9}

\frac{5 x}{9 x - 1}

f (x) = \frac{3 - x}{2 - x}

lo g_{5} (x - 2)

x^{2} - 8 x - 16 y - 64 = 0

What is the domain of f(x)=log_{1/2}(x-3) ?
The domain of f(x)=log_{1/2}(x-3) is x>3